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• 直线x+2y-3=0与圆x*2+y*2+x-6y+m=0相交于两点A,...(x+1/2)^2+(y-3)^2=37/4-m.∵OP垂直OQ,△PCQ是等腰直角三角形,直线到圆心的距离等于√2/2倍半径长.│-1/2+2×3-3│/√5=√2/2·√(37/4-m).解得m=27/4....

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